2.设直线 :dfrac (x-1)(1)=dfrac (y)(1)=dfrac (z-1)(-1) 及π -y+2z-1=0.-|||-(1)求直线L在平面π上的投影直线L0;-|||-(2)求L绕y轴旋转一周所成曲面的方程.

求直线dfrac (x-1)(1)=dfrac (y)(1)=dfrac (z-1)(-1)-|||-__ __在平面dfrac (x-1)(1)=dfrac

直线dfrac (x-1)(1)=dfrac (y-1)(0)=dfrac (z-1)(-1)-|||-__与直线dfrac (x-1)(1)=dfrac (y

直线dfrac (x-1)(2)=dfrac (y)(-1)=dfrac (z-2)(3)-|||-__与直线dfrac (x-1)(2)=dfrac (y)(

直线dfrac (x-1)(1)=dfrac (y)(2)=dfrac (z+3)(-2)-|||-__ __-|||-__与平面dfrac (x-1)(1)=

过直线_(1):dfrac (x-1)(1)=dfrac (y-2)(0)=dfrac (z-3)(-1)-|||-__ __且平行于直线_(1):dfrac

求直线l1: =dfrac {y-1)(-2)=dfrac (z-3)(-1) 的距离.

7.求通过点 P(1,0,-2) 而与平面 3x-y+2z-1=0 平行,且与直线-|||-dfrac (x-1)(4)=dfrac (y-3)(-2)=dfr

7.求通过点 P(1,0,-2) 而与平面 3x-y+2z-1=0 平行,且与直线-|||-dfrac (x-1)(4)=dfrac (y-3)(-2)=dfr

[题目]直线 dfrac (x+1)(-1)=dfrac (y-2)(1)=dfrac (z-1)(0) 与平面 4x+y+z=1 的-|||-夹角为() ()

[题目]-|||-求过点(0,1,2)且与直线 dfrac (x-1)(1)=dfrac (y-1)(-1)=dfrac (z)(2) 垂直相交的直线的方程.