3.要使函数φ(x )= ,dfrac {pi )(2)] (B)[π,2π] (C) [ 0,dfrac (pi )(2)] (D) [ dfrac (pi )(2),pi ]

(B) pi +dfrac (4)(3) (C) pi +2 . (D) pi +dfrac (8)(3)

[ 0,dfrac (pi )(2)] D. [ -sqrt (dfrac {pi )(2)},0]

设(x)=sin x, 则(dfrac (pi )(2))= __-|||-_.-|||-A cos dfrac (pi )(2)-|||-B o-|||-C-

设(X,Y)的分布函数为(x,y)=dfrac (1)({pi )^2}(dfrac (pi )(2)+arctan dfrac (x)(2))(dfrac (

(int )_(-dfrac {pi )(2)}^dfrac (pi {2)}dfrac (|x|sin x)(1+{cos )^3x}dx=(int )_(-

dfrac (pi )(3)B . dfrac (pi )(3)C . dfrac (pi )(3)D . dfrac (pi )(3)[单选题]复数1+i对应

f(x)= pi ,dfrac {pi )(2)lt xlt pi (D)0

(B) dfrac (pi )(3) (C) π/6, (D) dfrac (pi )(2)A、AB、BC、CD、DA、AB、BC、CD、D

dfrac (pi )(4) C. dfrac (pi )(2) D.π

设=(int )_(-dfrac {pi )(2)}^dfrac (pi {2)}dfrac (sin x)(1+{x)^2}(cos )^4xdx, =(in