极限lim _(xarrow {0)^+}dfrac ({int )_(0)^(x^4)dt(int )_(0)^xsin dfrac (t)(u)du}(1-{e)^-dfrac (1{8)}(x)^8}为( )

极限为( )

A. .

B. .

C. .

D. .

参考答案与解析:

相关试题

求下列极限: lim _(xarrow 0)[ dfrac ({int )_(0)^xsqrt (1+{t)^2}dt}(x)+dfrac ({int )_(0)^xsin tdt}({x)^2}]

求下列极限: lim _(xarrow 0)[ dfrac ({int )_(0)^xsqrt (1+{t)^2}dt}(x)+dfrac ({int )_(0

  • 查看答案
  • 求极限lim _(xarrow 0)dfrac ({int )_(0)^2xln (1+t)dt}(xsin x)

    求极限lim _(xarrow 0)dfrac ({int )_(0)^2xln (1+t)dt}(xsin x)求极限

  • 查看答案
  • 求极限lim _(xarrow 0)dfrac ({int )_(0)^x(1-cos t)dt}({x)^3}= (ost)dt/=()。

    求极限lim _(xarrow 0)dfrac ({int )_(0)^x(1-cos t)dt}({x)^3}= (ost)dt/=()。求极限。

  • 查看答案
  • 极限lim _(xarrow 0)dfrac ({int )_(0)^(x^2)(e)^tdt}(2x)=()A、 lim _(xarrow 0)dfrac ({int )_(0)^(x^2)(e)^

    极限lim _(xarrow 0)dfrac ({int )_(0)^(x^2)(e)^tdt}(2x)=()A、 lim _(xarrow 0)dfrac (

  • 查看答案
  • (1) lim _(xarrow 0)dfrac ({({int )_(0)^x(e)^(t^2)dt)}^2}({int )_(0)^xt(e)^2(t^2)dt} :

    (1) lim _(xarrow 0)dfrac ({({int )_(0)^x(e)^(t^2)dt)}^2}({int )_(0)^xt(e)^2(t^2)

  • 查看答案
  • lim _(xarrow 0)dfrac (x{int )_(0)^x((e)^2t-1)dt}(ln (1+{x)^3)}。

    lim _(xarrow 0)dfrac (x{int )_(0)^x((e)^2t-1)dt}(ln (1+{x)^3)}。。

  • 查看答案
  • lim _(xarrow 0)dfrac ({int )_(x)^0((e)^t+(e)^-t-2)dt}(1-cos x) ()-|||-__=()

    lim _(xarrow 0)dfrac ({int )_(x)^0((e)^t+(e)^-t-2)dt}(1-cos x) ()-|||-__=()=()A.

  • 查看答案
  • 计算极限:lim _(xarrow 0)[ dfrac ({{int )_(0)}^x(e)^-tcos tdt}({ln )^2(1+x)}-dfrac (1)(x)]

    计算极限:lim _(xarrow 0)[ dfrac ({{int )_(0)}^x(e)^-tcos tdt}({ln )^2(1+x)}-dfrac (1

  • 查看答案
  • 求极限lim _(xarrow 0)dfrac ({int )_(0)^xcos (t)^2dt}(ln (1+x))

    求极限lim _(xarrow 0)dfrac ({int )_(0)^xcos (t)^2dt}(ln (1+x))求极限

  • 查看答案
  • 41.求极限 lim _(xarrow 0)dfrac ({int )_(0)^xln (t+(e)^t)dt}(1-cos x)

    41.求极限 lim _(xarrow 0)dfrac ({int )_(0)^xln (t+(e)^t)dt}(1-cos x)

  • 查看答案