→ ((1)/(2sqrt(3))ln|(x^2+sqrt(3)x+1)/(x^2)-sqrt(3)x+1|+(1)/(2)arctanx+(1)/(6)arctanx^3+C)

注类似地，求$\int\frac{dx}{1+x^{6}}.$ → $\left(\frac{1}{2\sqrt{3}}ln\left|\frac{x^{2}+\sqrt{3}x+1}{x^{2}-\sqrt{3}x+1}\right|+\frac{1}{2}arctanx+\frac{1}{6}arctanx^{3}+C\right)$

参考答案与解析：

相关试题

求下列极限:-|||-(6) lim _(xarrow +infty )(x)^dfrac (3{2)}(sqrt (x+2)-2sqrt (x+1)+sqrt (x));: 求下列极限:-|||-(6) lim _(xarrow +infty )(x)^dfrac (3{2)}(sqrt (x+2)-2sqrt (x+1)+sqrt

查看答案

下列各对函数中,表示相同函数的一组是A) y=x+1和=sqrt ({(x+1))^2} B) y=ln x²和y=2ln xC)=sqrt ({(x+1))^2}和=sqrt ({(x+1))^2}: 下列各对函数中,表示相同函数的一组是A) y=x+1和=sqrt ({(x+1))^2} B) y=ln x²和y=2ln xC)=sqrt ({(x+1))^

查看答案

(int )_(1)^sqrt (3)dfrac (dx)({x)^2sqrt (1+{x)^2}};: (int )_(1)^sqrt (3)dfrac (dx)({x)^2sqrt (1+{x)^2}};

查看答案

设alpha_(1)=x(cossqrt(x)-1),alpha_(2)=sqrt(x)ln(1+sqrt[3](x)),alpha_(3)=sqrt[3](x+1)-1.当xto0^+时，以上3个无: 设alpha_(1)=x(cossqrt(x)-1),alpha_(2)=sqrt(x)ln(1+sqrt[3](x)),alpha_(3)=sqrt[3](x

查看答案

int dfrac (dx)(sqrt [3]{{(x+1))^2((x-1))^4}}: int dfrac (dx)(sqrt [3]{{(x+1))^2((x-1))^4}}

查看答案

int dfrac (dx)(sqrt [3]{{(x+1))^2((x-1))^4}}: int dfrac (dx)(sqrt [3]{{(x+1))^2((x-1))^4}}

查看答案

int dfrac (dx)(sqrt [3]{{(x+1))^2((x-1))^4}}: int dfrac (dx)(sqrt [3]{{(x+1))^2((x-1))^4}}

查看答案

(3) =dfrac (sqrt {x+2)((3-x))^4}({(x+1))^5}: (3) =dfrac (sqrt {x+2)((3-x))^4}({(x+1))^5}

查看答案

若lim_(xto3)(f(x)-2sqrt(x+1))/(x^2)-9=-(1)/(16),则f(x)=（）.: 若lim_(xto3)(f(x)-2sqrt(x+1))/(x^2)-9=-(1)/(16),则f(x)=（）.A. x+1B. x+5C. $\sqrt{x+

查看答案

求lim _(xarrow 3)dfrac (sqrt {x+1)-2}(x-3): 求lim _(xarrow 3)dfrac (sqrt {x+1)-2}(x-3)求

查看答案