利用洛必达法则求极限.-|||-lim _(xarrow {0)^+}((cos sqrt {x))}^dfrac (pi {x)}

参考答案与解析:

相关试题

1.用洛必达法则求下列各极限:-|||-(1) lim _(xarrow 0)dfrac (ln (1+x))(x)-|||-(3) lim _(xarrow a)dfrac (cos x-cos a

1.用洛必达法则求下列各极限:-|||-(1) lim _(xarrow 0)dfrac (ln (1+x))(x)-|||-(3) lim _(xarrow

  • 查看答案
  • 题目:1.用洛必达法则求下列极限:-|||-(1) lim _(xarrow 0)dfrac ({e)^x-cos x}(sin x)-|||-(2) lim _(xarrow 0)dfrac (ta

    题目:1.用洛必达法则求下列极限:-|||-(1) lim _(xarrow 0)dfrac ({e)^x-cos x}(sin x)-|||-(2) lim

  • 查看答案
  • 1.用洛必达法则求下列极限:-|||-(1) lim _(xarrow 0)dfrac (ln (1+x))(x)-|||-(4) lim _(xarrow pi )dfrac (sin 3x)(ta

    1.用洛必达法则求下列极限:-|||-(1) lim _(xarrow 0)dfrac (ln (1+x))(x)-|||-(4) lim _(xarrow p

  • 查看答案
  • 求极限lim _(xarrow {0)^+}dfrac (1-sqrt {cos x)}(x(1-cos sqrt {x))}

    求极限lim _(xarrow {0)^+}dfrac (1-sqrt {cos x)}(x(1-cos sqrt {x))}求极限

  • 查看答案
  • 1.用洛必达法则求下列极限.-|||-(1) lim _(xarrow 0)dfrac (ln (1+x))(x) :-|||-(3) lim _(xarrow a)dfrac (sin x-sin

    1.用洛必达法则求下列极限.-|||-(1) lim _(xarrow 0)dfrac (ln (1+x))(x) :-|||-(3) lim _(xarrow

  • 查看答案
  • 16.求极限 lim _(xarrow 0)dfrac (sqrt {1+xsin x)-sqrt (cos x)}({x)^2}

    16.求极限 lim _(xarrow 0)dfrac (sqrt {1+xsin x)-sqrt (cos x)}({x)^2}

  • 查看答案
  • 1.求下列极限:-|||-(1) lim _(xarrow 0)dfrac (sin 2x)(x);-|||-(3) lim _(xarrow dfrac {pi )(2)}dfrac (cos x)

    1.求下列极限:-|||-(1) lim _(xarrow 0)dfrac (sin 2x)(x);-|||-(3) lim _(xarrow dfrac {p

  • 查看答案
  • 用洛必达法则求下列极限:-|||-(9) lim _(xarrow +infty )dfrac (ln (1+dfrac {1)(x))}(arctan (x)-|||-(10) lim _(xarr

    用洛必达法则求下列极限:-|||-(9) lim _(xarrow +infty )dfrac (ln (1+dfrac {1)(x))}(arctan (x)

  • 查看答案
  • 求极限lim _(xarrow 0)dfrac (x)(sqrt {1-x)-1}= ()lim _(xarrow 0)dfrac (x)(sqrt {1-x)-1}= ()

    求极限lim _(xarrow 0)dfrac (x)(sqrt {1-x)-1}= ()lim _(xarrow 0)dfrac (x)(sqrt {1-x)

  • 查看答案
  • 1 计算下列极限1) lim _(xarrow 0)dfrac (sqrt {1+xsin x)-sqrt (cos x)}(xtan x);1) lim _(xarrow 0)dfrac (sqrt

    1 计算下列极限1) lim _(xarrow 0)dfrac (sqrt {1+xsin x)-sqrt (cos x)}(xtan x);1) lim _(

  • 查看答案