x .-m -1 O-|||--x m 1 =(a)_(4)(x)^4+(a)_(3)(x)^3+(a)_(2)(x)^2+(a)_(1)x+(a)_(0) ,则 _(4)+(a)_(3)+(a)_(2)+(a)_(1)+(a)_(0)= ()-|||-22.已知 -1 x -m-|||-m 1 -x-|||-(A) -(m)^4+4(m)^2 (B) ^4+4(m)^2 (C) -(m)^4+2(m)^2-|||-(D) ^4-4(m)^2 (E) -(m)^4-4(m)^2

5.求 f(x)与 g (x)的最大公因式:-|||-(1) (x)=(x)^4+(x)^3-3(x)^2-4x-1 (x)=(x)^3+(x)^2-x-1;-

5.求f(x)与g (x)的最大公因式:-|||-(1) (x)=(x)^4+(x)^3-3(x)^2-4x-1 (x)=(x)^3+(x)^2-x-1;-||

[题目]-|||-证明:-|||-x -1 0 0-|||-0 x -1 0 =(a)_(3)(x)^3+(a)_(2)(x)^2+(a)_(1)x+(a)_(

4.已知实数x满足x^2+(1)/(x^2)-3x-(3)/(x)+2=0.求x^3+(1)/(x^3)的值.4.已知实数x满足$x^{2}+\frac{1}{

) (x)_(1)+4(x)_(2)-2(x)_(3)+8(x)_(4)=2 -(x)_(1)+2(x)_(2)+3(x)_(3)+4(x)_(4)=1 (x)

x -1 0 0-|||-0 x -1 0 =(a)_(3)(x)^3+(a)_(2)(x)^2+(a)_(1)x+(a)_(0)-|||-(5)-|||-()

若多项式(x)=(x)^4+(x)^3-3(x)^2-4x-1 和 (x)=(x)^3+(x)^2-x-1，则f(x)和g(x)的公因式为（）。A、x+1B、x

设_(1),(X)_(2),(X)_(3),(X)_(4)独立同分布，服从分布_(1),(X)_(2),(X)_(3),(X)_(4) ，记_(1),(X)_(

设_(1),(X)_(2),(X)_(3),(X)_(4)是取自总体_(1),(X)_(2),(X)_(3),(X)_(4)的样本,_(1),(X)_(2),(

关于方程组_(1)-2(x)_(2)+3(x)_(3)-4(x)_(4)=4 _(1)-2(x)_(2)+3(x)_(3)-4