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(int )_(0)^dfrac (pi {4)}dfrac (x)(1+cos 2x)dx=( ) .(int )_(0)^dfrac (pi {4)}dfr
.int dfrac (1+{cos )^2x}(1+cos 2x)dx
( 20 int dfrac (dx)(1+cos 2x) ;
计算下列不定积分int dfrac (1)(1+cos 2x)dx计算下列不定积分
(3) (int )_(0)^dfrac (pi {4)}dfrac (x)(1+cos 2x)dx= () .-|||-(A) dfrac (pi )(8)+
int dfrac (sin x)(1+{cos )^2x}dx=-|||-__
)int dfrac (1)({cos )^2x(sin )^2x}dx.
[题目] int dfrac (x+sin x)(1+cos x)dx,
(int )_(-dfrac {pi )(2)}^dfrac (pi {2)}((cos )^2x+dfrac (xcos x)(1+{cos )^2x})dx
求不定积分int dfrac (1)(2x)sqrt (ln x)dx=().int dfrac (1)(2x)sqrt (ln x)dx=int dfrac