(4) (x)=sqrt [3]({x)^4} , (x)=xcdot sqrt [3](x);
曲线y=(x-1 )3√x^2的凹区间为( )y=(x-1 )3√x^2y=(x-1 )3√x^2y=(x-1 )3√x^2y=(x-1 )3√x^2曲线的凹区
int dfrac (dx)(sqrt [3]{{(x+1))^2((x-1))^4}}
int dfrac (dx)(sqrt [3]{{(x+1))^2((x-1))^4}}
int dfrac (dx)(sqrt [3]{{(x+1))^2((x-1))^4}}
解方程_(2)-3(x)_(3)+4(x)_(4)=-5-|||-x1- 2x3+324 =-4-|||-(x)_(1)+2(x)_(2)-5(x)_(4)=1
(1) int dfrac (3sqrt {x)}(x(sqrt {x)+sqrt [3](x))}dx
函数y=sqrt((x-1)/((x-3)(x-4)))在x=5处的导数为( )A. $\frac{7}{8}\sqrt{2}$B. $-\frac{7}{8}
做有理化dfrac (sqrt {x+2)-sqrt (3)}(x-1)做有理化
((X)_(1)+(X)_(2)+(X)_(3))/3 b.X1-|||-c. ((X)_(1)+(X)_(2))/2 d. (2(X)_(1)+(X)_(2)