1.-|||-若limf(x)存在,且 (x)=(x)^3+dfrac (2{x)^2+1}(x+1)+2lim _(xarrow 1)f(x) ,则 lim _(xarrow 1)f(x)= __ .

已知 lim _(xarrow 0)([ 1+x+dfrac {f(x))(x)] }^dfrac (1{x)}=(e)^3, 则 lim _(xarrow 0

[例8]设f(x )在 x=1 连续,且 lim _(xarrow 1)dfrac (f(x)-2)(x-1) 存在,则 (1)= __-|||-解:因为 li

A.lim _(xarrow 1)dfrac ({x)^2+x-2}({x)^2-1}=lim _(xarrow 1)dfrac ((x-1)(x+2))((x

设 (x+dfrac (1)(x))=(x)^2+dfrac (1)({x)^2}, 则 lim _(xarrow 3)f(x)= __

设 函数 f ( x ) 在 x = 1 处可导且lim _(xarrow 0)dfrac (f(1)-f(1-x))(2x)=1则 lim _(xarrow

设 lim _(xarrow 0)((1+x+dfrac {f(x))(x))}^dfrac (1{x)}=(e)^3 ,则 lim _(xarrow 0)((

①,设f(x)是以2为周期的可导函数,且 lim _(xarrow 1)dfrac (f(2x-1)-2f(3-2x))(ln x)=3 则-|||-lim _

计算函数极限(1)lim _(xarrow 1)dfrac (x-3)(x+2)(2)lim _(xarrow 1)dfrac (x-3)(x+2)(3)lim

(B) lim f(x)=0.-|||-(C) lim _(xarrow 1)f(x)=infty . D)limf(x)不存在,且 lim _(xarrow

(9)已知 lim _(xarrow a)f(x)=lim _(xarrow a)g(x), 则 lim _(xarrow a)dfrac (f(x))(g(x