曲线 =(x-1)((x-2))^2((x-3))^3((x-4))^4 的拐点是 () .-|||-(A)(1,0) (B)(2,0) (C)(3,0) (D)(4,0)

设函数(x)=x(x-1)(x-2)(x-3)(x-4)，则(x)=x(x-1)(x-2)(x-3)(x-4).A.0 B.24C.36 D.48设函数，则.A

、单选 设曲线为 =((x-1))^2((x-3))^2,-|||-其极值点个数为 ()()-|||-(4分-|||-A 0-|||-B 3-|||-C 1-|

若方程组 ) 7(x)_(1)+8(x)_(2)+9(x)_(3)=0 -(x)_(2)+2(x)_(3)=0 2(x)_(2)+t(x)_(3)=0 .=

解下列方程：(1)x2+x=0；(2)x2-2√3x=0；(3)3x2-6x=-3；(4)4x2-121=0；(5)3x(2x+1)=4x+2；(6)(x-4)

已知函数f（x）={2，-1≤x≤0，)x+2，0＜x＜2，)4，x≥2，).则f（3）= ____ ．已知函数f（x）=$\left\{\begin{arra

设 lim _(xarrow infty )dfrac ((x-1)(x-2)(x-3)(x-4)(x-5))({(3x-2))^2}=beta 则α,β的数

若函数(ln x-1)=3(x)^2+2x-1，则(ln x-1)=3(x)^2+2x-1=A -1B 0C 2D 4若函数，则=A -1B 0

) (x)_(1)+4(x)_(2)-2(x)_(3)+8(x)_(4)=2 -(x)_(1)+2(x)_(2)+3(x)_(3)+4(x)_(4)=1 (x)

过点(1,1,1)、 (-2,-2,2) 和(1,-1,1) 的平面方程是 ()-|||-A x+4z+3=0-|||-B x+3z-4=0-|||-C x+4

设_(1),(X)_(2),(X)_(3),(X)_(4)是取自总体_(1),(X)_(2),(X)_(3),(X)_(4)的样本,_(1),(X)_(2),(