求lim _(xarrow infty )dfrac (ln (x+sqrt {{x)^2+1)}-ln (x+sqrt ({x)^2-1})}({({e)^dfrac (1{x)}-1)}^2}

求极限 lim _(xarrow +infty )dfrac (ln (x+sqrt {{x)^2+1})-ln (x+sqrt ({x)^2-1})}( l

求下列极限-|||-lim _(xarrow 0)[ dfrac (1)(ln (x+sqrt {1+{x)^2})}-dfrac (1)(ln (1+x))]

求极限 lim _(xarrow +infty )((x+sqrt {1+{x)^2})}^dfrac (1{x)}

(1) =ln (x+sqrt ({x)^2+1})

函数 y=ln (x+sqrt(x^2+1)) 是()。A. 奇函数B. 偶函数C. 非奇非偶函数D. 既是奇函数又是偶函数

2.求极限 lim _(xarrow +infty )arcsin dfrac (x)(sqrt {{x)^2+1}+x}

(2) (x)=ln (x+sqrt (1+{x)^2});

6、极限 lim _(xarrow +infty )(sqrt ({x)^2+x}-sqrt ({x)^2+1})= () 。(较难)-|||-A、0 B、 d

求：lim _(xarrow +infty )(({x)^dfrac (1{x)}-1)}^dfrac (1{ln x)}求：

证明函数(x)=ln (x+sqrt ({x)^2+1})为奇函数.证明函数为奇函数.