(2) =ln tan dfrac (x)(2);

(2) lim _(xarrow 0)[ dfrac (1)(ln (1+{tan )^2x)}-dfrac (1)(ln (1+{x)^2)}]

(2) lim _(xarrow 0)[ dfrac (1)(ln (1+{tan )^2x)}-dfrac (1)(ln (1+{x)^2)}]

21.计算极限 lim _(xarrow {0)^+}dfrac (ln tan 5x)(ln tan 2x)

设(x)=((2-x))^tan dfrac (pi {2)x},(dfrac (1)(2)lt xlt 1),求(x)=((2-x))^tan dfrac (

期末考试-|||-求函数 s =ln tan dfrac (x)(2) 的导数 dfrac (dy)(dx)

求下列函数的导数:-|||-(1) =arcsin (sin x);-|||-(2) =arctan dfrac (1+x)(1-x);-|||-(3) =ln

求下列函数的导数:-|||-(1) =arcsin (sin x);-|||-(2) =arctan dfrac (1+x)(1-x);-|||-(3) =ln

如果^2+(z)^2=ln dfrac (z)(x),则^2+(z)^2=ln dfrac (z)(x)( ).A.^2+(z)^2=ln dfrac (

int dfrac (ln tan x)(cos xsin x)dx

(8) lim _(xarrow dfrac {pi )(2)}dfrac (tan x)(tan 3x)