29 设f(x)是以3为周期的可导函数且是偶函数, f'(-2)=-1 ,则-|||-.lim _(harrow 0)dfrac (h)(f(5-2sin h)-f(5))= .__ -|||-__

设函数f(x)满足lim _(harrow 0)dfrac (1)(h)[ f(5-dfrac (1)(3)h)-f(5)] =2,则lim _(harrow

已知f(x)为可导函数且 (1)=-2, 则 lim _(harrow 0)dfrac (f(1-h)-f(1-2h))(2h)=

[题目]设函数f (x)在 x=0 处连续,且 lim _(harrow 0)dfrac (f({h)^2)}({h)^2}=1,-|||-则 ()-|||-

6、单选-|||-f-|||-A .lim _(harrow 0)dfrac (f({x)_(0)+5h)-f((x)_(0)+2h)}(h)=f((x)_(0

(1)若f(x)在 =(x)_(0) 处可导,则 () .-|||-(A) lim _(harrow 0)dfrac (f({x)_(0)+2h)-f((x)_

1.设f(x)为可导函数,且 lim _(xarrow 0)dfrac (f(1)-f(1-x))(2x)=-1 ,则 f(1)= __

设 函数 f ( x ) 在 x = 0 处可导，且lim _(xarrow 0)dfrac (f(2x)-f(0))(ln (1+3x))=1，则f(0)=(

①,设f(x)是以2为周期的可导函数,且 lim _(xarrow 1)dfrac (f(2x-1)-2f(3-2x))(ln x)=3 则-|||-lim _

若极限lim _(harrow 0)dfrac (f({x)_(0)+2h)-f((x)_(0))}(h)=dfrac (1)(2)，则导数值lim _(har

(f(x)在 _{0)=(x)_(0) 处可导,且 lim _(harrow 0)dfrac (f({x)_(0)+2h)-f((x)_(0)-h)}(2h)=