已知反应 (H)_(2)(101325Pa)+S(b)_(2)(O)_(3)(UND)leftharpoons 2Sb+(H)_(2)O 在25℃时的 Delta G=-8364J/mol-|||-试计算下列电池的电动势,并指出电池的正负极:-|||-|(H)_(2)(101325Pa)|(H)_(2)O(pH=3)|S(b)_(2)(O)_(3) 固)|Sb

Delta (H)_(1)=akJcdot (mol)^-1-|||-反应Ⅱ: (g)+(H)_(2)O(g)leftharpoons C(O)_(2)(g)+

18.已知:-|||-①H2O(g)=H2(g)+2O2(g) H=+241.88kJ/mol-|||-②C(s)+2O2(g )=CO(g) △H=-110.

已知:( bigcirc (1)C(H)_(5)OH(g)+dfrac (1)(2)(O)_(2)(g)=C(O)_(2)(g)+2(H)_(2)(g) De

298.15K时,反应 (H)_(2)(O)_(2)(1)leftharpoons 2(H)_(2)O(1)+(O)_(2)(g) 的 (Delta )_(r)

(1)在硫酸工业中,通过下列反应使SO 2氧化成-|||-S _(3):2S(O)_(2)(g)+(O)_(2)(g)leftharpoons 2S(O)_(3

373 K 时，2(NaHC)({{O)}_3}( (s) )leftharpoons (N)({{a)}_2}(C)({{O)}_3}( (s) )+(C)(

判断反应 _(2)(H)_(5)OH(g)=(C)_(2)(H)_(4)(g)+(H)_(2)O(g)-|||-已知 Delta (H)_(m)O(kJ/mol

已知298 K时反应：3 ( Fe(s)) + 4 ( H)_2(O(g)) = (Fe)_3(O)_4((s)) + 4 ( H)_2((g))Delta_(

(H)_(2)(g)+(O)_(2)(g)=!=!= 2(H)_(2)O(l) Delta (H)_(3)=-572kJcdot mo(l)^-1-|||-_

298.15K时，反应(H)_(2)(O)_(2) (l) leftharpoons 2(H)_(2) O (l) +(O)_(2)(g)的(H)_(2)(O)