1.求下列函数的自然定义域:-|||-(1) =sqrt (3x+2);-|||-(2) =dfrac (1)(1-{x)^2};-|||-(3) =dfrac (1)(x)-sqrt (1-{x)^2};-|||-(4) =dfrac (1)(sqrt {4-{x)^2}};-|||-(5) =sin sqrt (x);-|||-(6) =tan (x+1);-|||-(7) =arcsin (x-3);-|||-(8) =sqrt (3-x)+dfrac (1)(x);-|||-(9) =ln (x+1);-|||-(10) =(e)^dfrac (1{x)}

参考答案与解析:

相关试题

1.求下列函数的自然定义域:-|||-(1) =sqrt (3x+2) ;-|||-(2) =dfrac (1)(1-{x)^2}-|||-(3) =dfrac (1)(x)-sqrt (1-{x)^

1.求下列函数的自然定义域:-|||-(1) =sqrt (3x+2) ;-|||-(2) =dfrac (1)(1-{x)^2}-|||-(3) =dfrac

  • 查看答案
  • [题目]求下列函数的自然定义域:-|||-(1) =sqrt (3x+2);-|||-(2) =dfrac (1)(1-{x)^2}-|||-(3) =dfrac (1)(x)-sqrt (1-{x)

    [题目]求下列函数的自然定义域:-|||-(1) =sqrt (3x+2);-|||-(2) =dfrac (1)(1-{x)^2}-|||-(3) =dfra

  • 查看答案
  • 1.求下列函数的自然定义域:-|||-(1) =sqrt (3x+2);-|||-(3) =dfrac (1)(x)-sqrt (1-{x)^2};-|||-(5) =sin sqrt (x);-||

    1.求下列函数的自然定义域:-|||-(1) =sqrt (3x+2);-|||-(3) =dfrac (1)(x)-sqrt (1-{x)^2};-|||-(

  • 查看答案
  • 求下列函数的自然定义域:(1)y=sqrt(3x+2);(2)y=dfrac(1)(1-{x)^2};(3)y=dfrac(1)(x)-sqrt(1-(x)^2);(4)y=dfrac(1)(sqrt

    求下列函数的自然定义域:(1)y=sqrt(3x+2);(2)y=dfrac(1)(1-{x)^2};(3)y=dfrac(1)(x)-sqrt(1-(x)^2

  • 查看答案
  • 函数 =arcsin sqrt (1-{x)^2}+dfrac (1)(sqrt {1-{x)^2}} 的定义域为 __ 。

    函数 =arcsin sqrt (1-{x)^2}+dfrac (1)(sqrt {1-{x)^2}} 的定义域为 __ 。

  • 查看答案
  • 函数(x)=dfrac (ln |x|)(sqrt {1-{x)^2}}的定义域是 A(x)=dfrac (ln |x|)(sqrt {1-{x)^2}} B ( -1 , 1 ) C ( -1 ,

    函数(x)=dfrac (ln |x|)(sqrt {1-{x)^2}}的定义域是 A(x)=dfrac (ln |x|)(sqrt {1-{x)^2}} B

  • 查看答案
  • [题目]函数 =dfrac (1)(x)-sqrt (1-{x)^2} 的定义域是-|||-__

    [题目]函数 =dfrac (1)(x)-sqrt (1-{x)^2} 的定义域是-|||-__

  • 查看答案
  • 设=dfrac (arcsin x)(sqrt {1-{x)^2}}(1)证明:=dfrac (arcsin x)(sqrt {1-{x)^2}}(2)求=dfrac (arcsin x)(sqrt

    设=dfrac (arcsin x)(sqrt {1-{x)^2}}(1)证明:=dfrac (arcsin x)(sqrt {1-{x)^2}}(2)求=df

  • 查看答案
  • =dfrac (x)(sqrt {1-{x)^2}},则=dfrac (x)(sqrt {1-{x)^2}}=_________.

    =dfrac (x)(sqrt {1-{x)^2}},则=dfrac (x)(sqrt {1-{x)^2}}=_________.,则=_________.

  • 查看答案
  • 求下列函数的定义域:(1)=sqrt (3x+2);(2)=sqrt (3x+2);(3)=sqrt (3x+2);(4)=sqrt (3x+2).

    求下列函数的定义域:(1)=sqrt (3x+2);(2)=sqrt (3x+2);(3)=sqrt (3x+2);(4)=sqrt (3x+2).求下列函数的

  • 查看答案