) ;-|||-(3) =(cos )^2dfrac (1)(x),x=0 =-|||-(4) y= ) x-1,xleqslant 1 3-x,xgt 1 . .x=1 --|||-,

) ;-|||-(3) =(cos )^2dfrac (1)(x),x=0 =-|||-,-|||-(4) y= ) x-1,xleqslant 1 3-x

) ;-|||-(3) =(cos )^2dfrac (1)(x),x=0 ;-|||-(4) y= ) x-1, xleqslant 1 3-x, x

已知(x-dfrac (1)(x))=dfrac ({x)^3-x}(1+{x)^4}-|||-__，求(x-dfrac (1)(x))=dfrac ({x)^

求极限lim _(xarrow 0)dfrac (1)({x)^3}[ ((dfrac {2+cos x)(3))}^x-1] -|||-__求极限

设f（x）=dfrac (2)(3)(x)^3,xleqslant 1 (x)^2,xgt 1，则f（x）在x=1处的（　　）设f（x）=，则f（x）在x=1处

设f（x）=dfrac (2)(3)(x)^3,xleqslant 1 (x)^2,xgt 1，则f（x）在x=1处的（　　）设f（x）=，则f（x）在x=1处

曲线y=(x-1 )3√x^2的凹区间为（ ）y=(x-1 )3√x^2y=(x-1 )3√x^2y=(x-1 )3√x^2y=(x-1 )3√x^2曲线的凹区

1.微分方程(1-(x)^2)(y)^2dfrac (dy)(dx)+(2(x)^2-1)(y)^3=(x)^3是(1-(x)^2)(y)^2dfrac (dy

直线dfrac (x-1)(1)=dfrac (y)(2)=dfrac (z+3)(-2)-|||-__ __-|||-__与平面dfrac (x-1)(1)=

lim _(xarrow 1)(dfrac (a)(1-{x)^2}+dfrac (x)(x-1))=dfrac (3)(2) = __