已知函数 (x)=dfrac (1)(2)sin (2x-dfrac (pi )(3)) x∈R,-|||-(1)求f(x)的最小正周期;-|||-(2)求f(x)在区间 [ -dfrac (pi )(4),dfrac (pi )(4)] - 上的最大值和最小值.

2.求下列函数在指定点的导数:-|||-(1)设 =f(x)=sin x-cos x, 求 (dfrac (pi )(4)), (dfrac (pi )(2))

设(X,Y)的分布函数为(x,y)=dfrac (1)({pi )^2}(dfrac (pi )(2)+arctan dfrac (x)(2))(dfrac (

设(x)=((2-x))^tan dfrac (pi {2)x},(dfrac (1)(2)lt xlt 1),求(x)=((2-x))^tan dfrac (

已知(x+dfrac (1)(x))=(x)^2+dfrac (1)({x)^2}-3，求f(x)已知，求f(x)

求lim _(xarrow dfrac {pi )(2)}dfrac (ln sin x)({(pi -2x))^2}求

10.设函数 (x)=sin dfrac (x)(3)+cos dfrac (x)(2), 求f(x)的周期.

(sin x)=dfrac (1)({cos )^2x} in (0,dfrac (pi )(2)),则(sin x)=dfrac (1)({cos )^2x}

(int )_(-dfrac {pi )(2)}^dfrac (pi {2)}dfrac (|x|sin x)(1+{cos )^3x}dx=(int )_(-

1.求下列极限：（2）lim _(xarrow dfrac {pi )(2)}dfrac (ln sin x)({(pi -2x))^2}1.求下列极限：（2）

2.求下列函数的极值:-|||-(6) (x)=sin x+cos x(-dfrac (pi )(2)leqslant xleqslant dfrac (pi