dfrac (1)(2)-|||-C .dfrac (sqrt {2)}(2)-|||-D .dfrac (sqrt {3)}(2)
sqrt (2) C. dfrac (sqrt {2)}(2) D.1
[题目]设 (x)=sqrt (1+{ln )^2x} 则 (e)=()-|||-A、 dfrac (sqrt {2)}(4)-|||-B、 dfrac (sq
(B) (mu ,dfrac (1)(sqrt {2pi )})-|||-(C) (mu ,dfrac (1)(2)), (D)(0,σ).
sqrt (2)pi -|||-C. dfrac (sqrt {2pi )}(4)-|||-D. dfrac (sqrt {2pi )}(8)
1.计算下列定积分:-|||-(8) (int )_(dfrac {1)(sqrt {2)}}^1dfrac (sqrt {1-{x)^2}}({x)^2}dx
(3)曲线 =sqrt (4ax-{x)^2} 在点 (a,sqrt (3)a) 处的曲率为 ()-|||-(A) dfrac (1)(a) (B)a (C)
6、极限 lim _(xarrow +infty )(sqrt ({x)^2+x}-sqrt ({x)^2+1})= () 。(较难)-|||-A、0 B、 d
int_(1)^sqrt(3) dfrac(d x)(x^2 sqrt(1+x^2))$ \int_{1}^{\sqrt{3}} \dfrac{d x}{x^{
下列凑微分的形式中错误的是( )A dfrac (1)(sqrt {{a)^2-(x)^2}}dx=d(arctan dfrac (x)(a))B dfr