设 gt 0, 求 (int )_(-a)^asqrt ({a)^2-(x)^2}ln dfrac (x+sqrt {1+{x)^2}}(3)dx,

设 gt 0, 则 =(int )_(-a)^asqrt ({a)^2-(x)^2}ln dfrac (x+sqrt {1+{x)^2}}(3)dx= __

求下列不定积分int ln (x+sqrt (1+{x)^2})dx求下列不定积分

求不定积分int dfrac (1)(2x)sqrt (ln x)dx=（）.int dfrac (1)(2x)sqrt (ln x)dx=int dfrac

计算下列积分:(3) int (ln )^2(x+sqrt (1+{x)^2})dx ;计算下列积分:(3);

int dfrac (ln x)({(1+{x)^2)}^3/2}dx; ;

求下列极限-|||-lim _(xarrow 0)[ dfrac (1)(ln (x+sqrt {1+{x)^2})}-dfrac (1)(ln (1+x))]

分) 设 (x)=(int )_({x)^2}dfrac (t)(sqrt {1+{t)^3}}dt 求 =(int )_(0)^1xF(x)dx

int dfrac ({x)^3}(sqrt {1+{x)^2}}dx,

int ln (sqrt (1+{x)^2}-x)dx;

求定积分(int )_(1)^sqrt (3)dfrac (1)({x)^2sqrt (1+{x)^2}}dx求定积分