[题目]证明:当 gt 1 时, ^x-1gt dfrac (1)(2)(x)^2+dfrac (1)(2)

【题文】已知(x+dfrac (1)(x))=(x)^2+dfrac (1)({x)^2}，求(x+dfrac (1)(x))=(x)^2+dfrac (1)(

[题目]设 (x+dfrac (1)(x))=(x)^2+dfrac (1)({x)^2}, 则f(x)= __

定积分 ^2-dfrac (1)(x)+C ()()-|||-A dfrac (1)(2)(x)^2+dfrac (1)(x)+C-|||-B dfrac (1

[题目]当 gt 0 时,证明: -dfrac ({x)^2}(2)lt ln (1+x)lt x.

(1)已知 (x+dfrac (1)(x))=(x)^2+dfrac (1)({x)^2}, 则 f(x)= __ ;

... +({X)_(n)}^2)-|||-;(5) (mu )^2+dfrac (1)(3)((X)_(1)+(X)_(2)+(X)_(3))-|||-;(6

已知(x+dfrac (1)(x))=(x)^2+dfrac (1)({x)^2}-3，求f(x)已知，求f(x)

已 知 函数 (x+dfrac (1)(x))=(x)^2+dfrac (1)({x)^2}, 则 f(x)=-|||-__

【题文】已知：(x-dfrac (1)(x))=(x)^2+dfrac (1)({x)^2}-|||-__，则f(x)=________.【题文】已知：，则f(

证明:当 gt 0 时,有不等式 arctan x+dfrac (1)(x)gt dfrac (pi )(2)