设dfrac(x)({x)^2 -3x+1} =1，求dfrac({x)^3}({x)^6-27(x)^3+1}的值.

设$\dfrac{x}{{x}^{2} -3x+1} =1$，求$\dfrac{{x}^{3}}{{x}^{6}-27{x}^{3}+1}$的值.

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