sin (20)^circ cos (10)^circ -cos (160)^circ sin (10)^circ =-|||-()-|||-
^circ +(25)^circ =-|||-^circ +(81)^circ =-|||-^circ +(140)^circ =-|||-^circ -(25
dfrac (sqrt {3)}(2)sin (15)^circ +dfrac (1)(2)cos (15)^circ 的值为( )A.dfrac
16.单选题-|||-已知 sin (36.9)^circ =0.6 ,cos (36.9)^circ =0.8 。将复数 =1-|||-angle -(36.
^circ -dfrac (4)(2)-|||-:^circ +dfrac ({varphi )^1}(2) D. ^circ -dfrac ({varphi
2.比较温度的高低。-|||-^circ Cbigcirc (5)^circ C-|||-^circ Cbigcirc -(2)^circ C-|||-^cir
画下面各角。-|||-^circ -|||-^circ -|||-^circ
一铝制空心球,内径40mm,外径80mm,内外壁温度分别为^circ C(50)^circ C,外壁覆盖一层导热系数为^circ C(50)^circ C的保温
测者纬度 20^circ N,天体赤纬 25^circ N,该天体上中天的方位为 ________ 。A. $000^\circ$B. $090^\circ$C
一厚度为50(mm)的无限大平壁,其稳态温度分布为: t = a + bx^2 (^circ(C)),x 的单位为(m)。式中,a = 200^circ(C),