（x^2-1，x+1）=（）

(x)=dfrac ({x)^2-1}((x+1)(x-2))

4、微分方程 +xydy=(y)^2dx+ydy 的通解为-|||-A、 ^2+1=C((x-1))^2 B、 ^2-1=C(x+1)-|||-C、 ^2-1=

A.lim _(xarrow 1)dfrac ({x)^2+x-2}({x)^2-1}=lim _(xarrow 1)dfrac ((x-1)(x+2))((x

求极限 lim _(xarrow +infty )dfrac (ln (x+sqrt {{x)^2+1})-ln (x+sqrt ({x)^2-1})}( l

3.求解下列方程.-|||-x+1 2-|||-(1) 2 x+1 } -1 1 x+1

微分方程(x+1)y-2y=((x+1))^2 的通解 A (x+1)y-2y=((x+1))^2B (x+1)y-2y=((x+1))^2C (x+1)y-

[单选题]（x^2+2x+1，x^2-1）（）A . 2x-1B . 2x+1C . x+1D . x-1

1.设 (dfrac (1)(x))=x((dfrac {x)(x+1))}^2, 则 f(x)= ()-|||-(A) dfrac (1)(x)((dfrac

5.求解下列方程:-|||-x+1 2 -1-|||-(1) 2 x+1 1 =0;-|||--1 1 x+1

将函数(x)=dfrac (1)(x+1)展开成(x-1)的幂级数2.计算(x)=dfrac (1)(x+1),其中(x)=dfrac (1)(x+1)是锥面(