1.设 (dfrac (1)(x))=x((dfrac {x)(x+1))}^2, 则 f(x)= ()-|||-(A) dfrac (1)(x)((dfrac {1)(x+1))}^2 (B) ((dfrac {1)(x+1))}^2-|||-(C) dfrac (1)(x)((dfrac {x)(x+1))}^2 (D)x (x/(x+1))^2

参考答案与解析：

相关试题

设(x)+(x)^2f(dfrac (1)(x))=dfrac ({x)^2+2x}(x+1) 求f(x)

设(x)+(x)^2f(dfrac (1)(x))=dfrac ({x)^2+2x}(x+1) 求f(x)设

  • 查看答案

    • 将函数(x)=dfrac (1)(x+1)展开成(x-1)的幂级数2.计算(x)=dfrac (1)(x+1),其中(x)=dfrac (1)(x+1)是锥面(x)=dfrac (1)(x+1)被平面

    将函数(x)=dfrac (1)(x+1)展开成(x-1)的幂级数2.计算(x)=dfrac (1)(x+1),其中(x)=dfrac (1)(x+1)是锥面(

  • 查看答案

    • [例26]已知 (dfrac (x+1)(x-1))=2f(x)-3x, 则 f(x)= __-|||-解:令 =dfrac (x+1)(x-1), 则 =dfrac (t+1)(t-1), 得到-|

    [例26]已知 (dfrac (x+1)(x-1))=2f(x)-3x, 则 f(x)= __-|||-解:令 =dfrac (x+1)(x-1), 则 =df

  • 查看答案

    • 6.(2024)函数f(x) =dfrac (x+1)({x)^2+x+1}的单调增区间().dfrac (x+1)({x)^2+x+1}

    6.(2024)函数f(x) =dfrac (x+1)({x)^2+x+1}的单调增区间().dfrac (x+1)({x)^2+x+1}6.(2024)函数f

  • 查看答案

    • 6.(2024)函数f(x) =dfrac (x+1)({x)^2+x+1}的单调增区间().dfrac (x+1)({x)^2+x+1}

    6.(2024)函数f(x) =dfrac (x+1)({x)^2+x+1}的单调增区间().dfrac (x+1)({x)^2+x+1}6.(2024)函数f

  • 查看答案

    • 1.设 (x)=dfrac (1)(1-{x)^2}, 求 (-x),f[ f(x)] ,f[ dfrac (1)(f(x))]

    1.设 (x)=dfrac (1)(1-{x)^2}, 求 (-x),f[ f(x)] ,f[ dfrac (1)(f(x))]

  • 查看答案

    • (int )_(-1)^1(dfrac (sin x+1)(1+{x)^2}+(x)^4)dxA (int )_(-1)^1(dfrac (sin x+1)(1+{x)^2}+(x)^4)dx B

    (int )_(-1)^1(dfrac (sin x+1)(1+{x)^2}+(x)^4)dxA (int )_(-1)^1(dfrac (sin x+1)(

  • 查看答案

    • (2) lim _(xarrow infty )((dfrac {x+1)(x-1))}^-dfrac (x{2)}= () ;-|||-(A)1 (B) ^dfrac (1{2)} (C)0 (D)

    (2) lim _(xarrow infty )((dfrac {x+1)(x-1))}^-dfrac (x{2)}= () ;-|||-(A)1 (B) ^d

  • 查看答案

    • lim _(xarrow 0)[ dfrac (1)(2x)-dfrac (1)(x({e)^x+1)}] ;

    lim _(xarrow 0)[ dfrac (1)(2x)-dfrac (1)(x({e)^x+1)}] ;

  • 查看答案

    • (x)=dfrac ({x)^2-1}((x+1)(x-2))

    (x)=dfrac ({x)^2-1}((x+1)(x-2))

  • 查看答案