设(x)+(x)^2f(dfrac (1)(x))=dfrac ({x)^2+2x}(x+1) 求f(x)

1.设 (dfrac (1)(x))=x((dfrac {x)(x+1))}^2, 则 f(x)= ()-|||-(A) dfrac (1)(x)((dfrac

1.设 (x)=dfrac (1)(1-{x)^2}, 求 (-x),f[ f(x)] ,f[ dfrac (1)(f(x))]

2 基础出 已知 (x)=dfrac (x-1)(x+1) ,求 f(-2) ,f[f(x)].

[例26]已知 (dfrac (x+1)(x-1))=2f(x)-3x, 则 f(x)= __

求定积分：∫(;)_(0)^2f（x）dx，其中f（x）={x+1，x≤1)(1)/(2){x)^2，x＞1}.．求定积分：∫${\;}_{0}^{2}$f（x

44.设 (x)=f(x)(dfrac (1)({2)^x+1}-dfrac (1)(2)), 已知f(x)为奇函数,判断F(x)的奇偶性.

[例26]已知 (dfrac (x+1)(x-1))=2f(x)-3x, 则 f(x)= __-|||-解:令 =dfrac (x+1)(x-1), 则 =df

11.设 (x)=dfrac (x)(sqrt {1+{x)^2}} 求 [ f(x)] , f[ f(x)] .

设 (x+dfrac (1)(x))=dfrac ({x)^2}({x)^4+1}(xneq 0), 求f(x)。

.已知 (dfrac (1)(x))=dfrac (4)(x)+2(x)^2+1, 求f(x), ((x)^2+1)