以下程序的输出结果是#include <conio.h>#include <stdio.h>#define M 100void fun（int m, int *a, int *n）{ int i,j=0; for（i=1;i<=m;i++） if（i%7==0||i%11==0） a[j++]=i; *n=j;}main(){ int aa［M］,n,k; clrscr(); fun（100,aa,&n）; for（k=0;k<n;k++） if（（k+1）%20==0）printf（"＼n"）; else printf（"%d",aa［k］）; printf（"＼n"）; }

[主观题]#include <conio.h>#include <stdio.h>int fun（int *s, int t, int *k）{ int i;*k=0;(15)if（s［*k］<s［i］）*k=i;return(16);}main（）{int a［10］={ 876,675,896,101,301,401,980,431,451,777},k;clrscr（）;fun（a, 10, &k）;printf（"%d, %d＼n ", k, a［k］）;

[单选题]以下程序输出的结果是#include<stdio.h>#include<string.h>main(){ char w[][10]={"ABCD","EFGH","IJKL","MNOP"},k;for(k=1;k<3;k++) printf("%s/n",&w[k][k]);}A．ABCD FGH KLB．ABC EFG IJ MC．EFG JK 0D．FGH KL

[单选题]以下程序输出的结果是#include<stdio.h>#include<string.h>main(){ char w[][10]={"ABCD","EFGH","IJKL","MNOP"},k;for(k=1;k<3;k++) printf("%s/n",&w[k][k]);}A．ABCD FGH KLB．ABC EFG IJ MC．EFG JK 0D．FGH KL

[单选题]下面程序的输出结果是#include<stdio.h>#include<string.h>main(){ char *p1="abc",*p2="ABC",str[50]= "xyz";strcpy(str+2,strcat(p1,p2));printf("%s/n",str);}A．xyzabcABCB．zabcABCC．xyabcABCD．yzabcABC

[单选题]以下程序的输出结果是#include<stdio.h>struct st{ int x;int *y;}*p;int dt[4]={10,20,30,40};struct st aa[4]={50,&dt[0],60,&dt[0],60,&dt[0],60,&dt[0],};main(){ p=aa;printf("%d/n",++(p->x));}A．10B．11C．51D．60

[单选题]以下程序的输出结果是#include<stdio.h>struct st{ int x;int *y;}*p;int dt[4]={10,20,30,40};struct st aa[4]={50,&dt[0],60,&dt[0],60,&dt[0],60,&dt[0],};main(){ p=aa;printf("%d/n",++(p->x));}A．10B．11C．51D．60

[主观题]以下程序的输出结果是_[13]_______#include <stdio.h>#include <string.h>char *fun（char *t）{ char *p=t;return（p+strlen（t）/2）;}main（）{ char *str="abcdefgh";str=fun（str）;puts（str）;}

[试题]以下程序的输出结果是_[19]_______#include <stdio.h>#define M 5#define N M+Mmain（）{ int k;k=N*N*5; printf（"%d/n",k）;}

[单选题]以下程序的输出结果是#include <stdio.h>void prt (int *x, int*y, int*z){printf("%d,%d,%d/n",++*x,++*y,*(z++));}main(){int a=10,b=40,c=20;prt (&a,&b,&c);prt (&a,&b,&c);}A．11,42, 31 12,22,41B．11,41,20 12,42,20C．11,21,40 11,21,21D．11

[试题]以下程序的输出结果是( 10 )。#include .<stdio.h>Main( ){ char a,b;for( a=0; a<20; a+=7) { b=a% 10; putchar(b+'0'); }}