[问答题]

已知,求tan(α-2β)的值。

参考答案与解析:

相关试题

已知,,(1)求tan2α的值:(2)求β。

[问答题] 已知,,(1)求tan2α的值:(2)求β。

  • 查看答案
  • 已知: alpha_1, alpha_2, alpha_3 线性无关,beta_1 = 2alpha_2 - alpha_3,beta_2 = -alpha_1 + 2alpha_2,beta_3 =

    已知: alpha_1, alpha_2, alpha_3 线性无关,beta_1 = 2alpha_2 - alpha_3,beta_2 = -alpha_1

  • 查看答案
  • 1 1-|||-已知α= 1 ,= 2 , =alpha beta ^T, 求A^4.-|||-1 0

    1 1-|||-已知α= 1 ,= 2 , =alpha beta ^T, 求A^4.-|||-1 0

  • 查看答案
  • 已知alpha_(1),alpha_(2),beta,gamma均为3维列向量,又A=(alpha_(1),alpha_(2),beta),B=(alpha_(1),alpha_(2),gamma),

    已知alpha_(1),alpha_(2),beta,gamma均为3维列向量,又A=(alpha_(1),alpha_(2),beta),B=(alpha_(

  • 查看答案
  • 已知 alpha_1, alpha_2, alpha_3, beta, gamma 均为 4 维列向量,又 A = (alpha_1, alpha_2, alpha_3, beta),B = (alp

    已知 alpha_1, alpha_2, alpha_3, beta, gamma 均为 4 维列向量,又 A = (alpha_1, alpha_2, alp

  • 查看答案
  • 8.已知alpha=(1,2,3),beta=(1,(1)/(2),(1)/(3)),矩阵A=alpha^Tbeta,其中alpha^T是alpha的转置,求A^n(n为正整数)。

    8.已知alpha=(1,2,3),beta=(1,(1)/(2),(1)/(3)),矩阵A=alpha^Tbeta,其中alpha^T是alpha的转置,求A

  • 查看答案
  • (6)已知alpha_(1),alpha_(2),alpha_(3),beta,gamma均为四维列向量,又A=[alpha_(1),alpha_(2),alpha_(3),beta],B=[alph

    (6)已知alpha_(1),alpha_(2),alpha_(3),beta,gamma均为四维列向量,又A=[alpha_(1),alpha_(2),alp

  • 查看答案
  • (6)已知alpha_(1),alpha_(2),alpha_(3),beta,gamma均为四维列向量,又A=[alpha_(1),alpha_(2),alpha_(3),beta],B=[alph

    (6)已知alpha_(1),alpha_(2),alpha_(3),beta,gamma均为四维列向量,又A=[alpha_(1),alpha_(2),alp

  • 查看答案
  • beta_1 = alpha_1, beta_2 = alpha_1 + alpha_2, beta_3 = alpha_1 + alpha_2 + alpha_3, 记A = [alpha_1, a

    beta_1 = alpha_1, beta_2 = alpha_1 + alpha_2, beta_3 = alpha_1 + alpha_2 + alpha

  • 查看答案
  • 设 alpha (alpha )_(1),(alpha )_(2),(alpha )_(3),(beta )_(1),(beta )_(2) 均为四维列向量矩阵,alpha (alpha )_(1),

    设 alpha (alpha )_(1),(alpha )_(2),(alpha )_(3),(beta )_(1),(beta )_(2) 均为四维列向量矩阵

  • 查看答案