已知
,求tan(α-2β)的值。
[问答题] 已知,,(1)求tan2α的值:(2)求β。
已知: alpha_1, alpha_2, alpha_3 线性无关,beta_1 = 2alpha_2 - alpha_3,beta_2 = -alpha_1
1 1-|||-已知α= 1 ,= 2 , =alpha beta ^T, 求A^4.-|||-1 0
已知alpha_(1),alpha_(2),beta,gamma均为3维列向量,又A=(alpha_(1),alpha_(2),beta),B=(alpha_(
已知 alpha_1, alpha_2, alpha_3, beta, gamma 均为 4 维列向量,又 A = (alpha_1, alpha_2, alp
8.已知alpha=(1,2,3),beta=(1,(1)/(2),(1)/(3)),矩阵A=alpha^Tbeta,其中alpha^T是alpha的转置,求A
(6)已知alpha_(1),alpha_(2),alpha_(3),beta,gamma均为四维列向量,又A=[alpha_(1),alpha_(2),alp
(6)已知alpha_(1),alpha_(2),alpha_(3),beta,gamma均为四维列向量,又A=[alpha_(1),alpha_(2),alp
beta_1 = alpha_1, beta_2 = alpha_1 + alpha_2, beta_3 = alpha_1 + alpha_2 + alpha
设 alpha (alpha )_(1),(alpha )_(2),(alpha )_(3),(beta )_(1),(beta )_(2) 均为四维列向量矩阵