已知,
,
(1)求tan2α的值:
(2)求β。
[问答题] 已知,求tan(α-2β)的值。
1 1-|||-已知α= 1 ,= 2 , =alpha beta ^T, 求A^4.-|||-1 0
8.已知alpha=(1,2,3),beta=(1,(1)/(2),(1)/(3)),矩阵A=alpha^Tbeta,其中alpha^T是alpha的转置,求A
已知: alpha_1, alpha_2, alpha_3 线性无关,beta_1 = 2alpha_2 - alpha_3,beta_2 = -alpha_1
已知 (alpha )_(1)=(1,2,-3), (alpha )_(2)=(2,-1,-1),(alpha )_(1)=(1,2,-3), (alpha )
已知alpha_(1),alpha_(2),beta,gamma均为3维列向量,又A=(alpha_(1),alpha_(2),beta),B=(alpha_(
4.已知alpha=(1,1,-1)^T,beta=(1,2,1)^T,A=alphabeta^T,f(x)=(x-1)^3,求f(A)4.已知$\alpha=
beta_1 = alpha_1, beta_2 = alpha_1 + alpha_2, beta_3 = alpha_1 + alpha_2 + alpha
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已知alpha_{1),alpha_(2)}是R^2的一组基,求从基alpha_(1)+2alpha_(2),3alpha_(1)+5alpha_(2)到基-a