4.已知alpha=(1,1,-1)^T,beta=(1,2,1)^T,A=alphabeta^T,f(x)=(x-1)^3,求f(A)

已知向量(alpha )_(1)=((1,2,1))^T, (alpha )_(2)=((2,3,a))^T, =((1,a+2,-2))^T，(alpha )

[例26]已知 (dfrac (x+1)(x-1))=2f(x)-3x, 则 f(x)= __-|||-解:令 =dfrac (x+1)(x-1), 则 =df

1 1-|||-已知α= 1 ,= 2 , =alpha beta ^T, 求A^4.-|||-1 0

设向量组 _(1)=((1,2,3,3))^T, (alpha )_(2)=((1,-1,2,1))^T (alpha )_(3)=((1,1,0,1))^T,

2.求向量组: (alpha )_(1)=((1,1,3,1))^T (alpha )_(2)=((-1,1,-1,3))^T, (alpha )_(3)=((

( 1 ) 求 _(1)=((-1,2,1))^T (beta )_(2)=((1,0,b))^7的值 ; ( 2 ) 写出_(1)=((-1,2,1))^T

已知(alpha )_(1)=((1,1,2,2))^T, (alpha )_(2)=((1,-1,4,0))^T (alpha )_(3)=((1,0,3,1

2 基础出 已知 (x)=dfrac (x-1)(x+1) ,求 f(-2) ,f[f(x)].

设向量组 (alpha )_(1)=((0,1,1))^T, (alpha )_(2)=((1,0,1))^T (alpha )_(3)=((2,1,0))^T

设向量(alpha )_(1)=((1,1,-1))^T (alpha )_(2)=((0,2,1))^T,(alpha )_(1)=((1,1,-1))^T