[名词解释]

隔阂gé hé

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什么是传播隔阂?

[问答题] 什么是传播隔阂?

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  • _(2)(H)_(5)OH(g)+(H)_(2)O(g)=2(H)_(2)(g)+C(H)_(2)COOH(g) Delta (H)_(1) K-|||-Ⅱ. _(2)(H)_(5)OH(g)=C

    _(2)(H)_(5)OH(g)+(H)_(2)O(g)=2(H)_(2)(g)+C(H)_(2)COOH(g) Delta (H)_(1) K-|||-Ⅱ

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  • _(2)(H)_(6)(g)=!=!= (C)_(2)(H)_(4)(g)+(H)_(2)(g) Delta (H)_(1)=+137kJcdot (mol)^-1-|||-Ⅱ. (O)_(2)(g

    _(2)(H)_(6)(g)=!=!= (C)_(2)(H)_(4)(g)+(H)_(2)(g) Delta (H)_(1)=+137kJcdot (mol)

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  • (rm C(g)+H_2O(g) {!=!=!=) CO(g)+H_2(g)} Delta H_2iii.(rm C(s)+2H_2(g) {!=!=!=) CH_4(g)} Delt

    (rm C(g)+H_2O(g) {!=!=!=) CO(g)+H_2(g)} Delta H_2iii.(rm C(s)+2H_2(g) {!=!=!

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  • 在1000K,反应_(z)+2(H)_(2)(g)=C(H)_(4)(g)的标准摩尔反应焓_(z)+2(H)_(2)(g)=C(H)_(4)(g)与温度无关,_(z)+2(H)_(2)(g)=C(H)

    在1000K,反应_(z)+2(H)_(2)(g)=C(H)_(4)(g)的标准摩尔反应焓_(z)+2(H)_(2)(g)=C(H)_(4)(g)与温度无关,_

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  • Delta (H)_(1)=akJcdot (mol)^-1-|||-反应Ⅱ: (g)+(H)_(2)O(g)leftharpoons C(O)_(2)(g)+(H)_(2)(g)-|||-Delta

    Delta (H)_(1)=akJcdot (mol)^-1-|||-反应Ⅱ: (g)+(H)_(2)O(g)leftharpoons C(O)_(2)(g)+

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  • 6,水煤气发生炉中共有C(s),H 20(g),C 0(g),C 02(g),H 2(g)五种物质,其间能发生反应:CO 2(g)+C(s)=2 CO(g),H 2 O(g)+C(s)=CO(g)+H

    6,水煤气发生炉中共有C(s),H 20(g),C 0(g),C 02(g),H 2(g)五种物质,其间能发生反应:CO 2(g)+C(s)=2 CO(g),H

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  • 工业上用乙苯脱氢制苯乙烯-|||-._(6)(H)_(5)(C)_(2)(H)_(5)(g)=!=!= (C)_(6)(H)_(5)(C)_(2)(H)_(3)(g)+(H)_(2)(g) .-|||

    工业上用乙苯脱氢制苯乙烯-|||-._(6)(H)_(5)(C)_(2)(H)_(5)(g)=!=!= (C)_(6)(H)_(5)(C)_(2)(H)_(3)

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  • 用键焓来估算反应热时,反应_(2)(H)_(6)(g)arrow (C)_(2)(H)_(4)(g)+(H)_(2)(g)的热效应_(2)(H)_(6)(g)arrow (C)_(2)(H)_(4)(

    用键焓来估算反应热时,反应_(2)(H)_(6)(g)arrow (C)_(2)(H)_(4)(g)+(H)_(2)(g)的热效应_(2)(H)_(6)(g)a

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  • (H)_(2)(g)+(O)_(2)(g)=!=!= 2(H)_(2)O(l) Delta (H)_(3)=-572kJcdot mo(l)^-1-|||-_(2)S(g)=!=!= S(s)+(H

    (H)_(2)(g)+(O)_(2)(g)=!=!= 2(H)_(2)O(l) Delta (H)_(3)=-572kJcdot mo(l)^-1-|||-_

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