设函数 (x)=(e)^dfrac (1{x-1)}dfrac (ln |x+2|)({x)^2+x-6}求(x)=(e)^dfrac (1{x-1)}dfrac (ln |x+2|)({x)^2+x-6} 的间断点并判断其类型

求下列函数的反函数： (1) =dfrac (x+2)(x-2); (1) =dfrac (x+2)(x-2); (1) =dfrac (x+2)(x-2);求

设函数=dfrac ({x)^2}(x-1),则=dfrac ({x)^2}(x-1)=________.设函数,则=________.

2 , 1 B . 1 , 2 C . (x)=dfrac ({e)^x-1}(x), 1D . (x)=dfrac ({e)^x-1}(x), 2设函数，若当

已知函数(x)=dfrac (x)(x+2)求 (x)=dfrac (x)(x+2)。已知函数求。

A.lim _(xarrow 1)dfrac ({x)^2+x-2}({x)^2-1}=lim _(xarrow 1)dfrac ((x-1)(x+2))((x

int dfrac (ln x-1)({x)^2}dx=______________________

求极限 lim _(xarrow 1)(dfrac (x)(x-1)-dfrac (1)(ln x)) .

设函数 (x)=dfrac (1)({e)^dfrac (x{x-1)}-1} 则-|||-

lim _(xarrow 1)(dfrac (x)(x-1)-dfrac (1)(ln x))-|||-__ __

lim _(xarrow 1)(dfrac (x)(x-1)-dfrac (1)(ln x))-|||-__ __