求下列函数的反函数： (1) =dfrac (x+2)(x-2); (1) =dfrac (x+2)(x-2); (1) =dfrac (x+2)(x-2);

[题目]求下列函数的反函数:-|||-(1) =dfrac (x+2)(x-2);-|||-(2) =(x)^3+2;-|||-(3) =1+lg (2x-3)

函数(x)=dfrac (1)(x-2)的间断点是(x)=dfrac (1)(x-2)(x)=dfrac (1)(x-2)、(x)=dfrac (1)(x-2)

已知函数(x)=dfrac (x)(x+2)求 (x)=dfrac (x)(x+2)。已知函数求。

设函数 (x)=(e)^dfrac (1{x-1)}dfrac (ln |x+2|)({x)^2+x-6}求(x)=(e)^dfrac (1{x-1)}dfra

计算函数极限(1)lim _(xarrow 1)dfrac (x-3)(x+2)(2)lim _(xarrow 1)dfrac (x-3)(x+2)(3)lim

函数(x)=dfrac (|x|sin (x-2))(x(x-1){(x-2))^2}在下列哪个区间内有界（　　）函数在下列哪个区间内有界（　　）A. （-1，

[例1] 若函数 (x+2)=sin 2x, 求f(x), (dfrac (1)(x)) 女-|||--10 A

求极限lim _(xarrow 2)(dfrac (1)({x)^2-3x+2})-(dfrac (1)(x-2))-|||-__求极限

(x)=dfrac ({x)^2-1}((x+1)(x-2))

求方程dfrac (dy)(dx)-dfrac (2y)(x+2)=((x+2))^dfrac (5{2)}的通解求方程的通解