tan dfrac (pi )(6)= ()-|||-

化 tan dfrac (pi -C)(2)=-pi `D =dfrac (E+C)(2)=cotdfrac (4)(2)-|||-6三年 therefore

(8) lim _(xarrow dfrac {pi )(2)}dfrac (tan x)(tan 3x)

(8) lim _(xarrow dfrac {pi )(2)}dfrac (tan x)(tan 3x)

[题目]已知 tan theta -tan (theta +dfrac (pi )(4))=7, 则 tan theta =-|||-()-|||-

(int )_(0)^dfrac (pi {4)}(tan )^2xdx=1-dfrac (pi )(4) __-|||-__下列式子或叙述不正确的是A.B.设

1357.已知 tan x=1, in (dfrac (pi )(2),dfrac (3pi )(2)), 则 =-|||-

设(x)=((2-x))^tan dfrac (pi {2)x},(dfrac (1)(2)lt xlt 1),求(x)=((2-x))^tan dfrac (

lim _(narrow infty )(tan )^n(dfrac (pi )(4)+dfrac (2)(n)) __-|||-__

2.求微分方程 =dfrac (y)(x)+tan dfrac (y)(x), 满足 |,x|=dfrac (pi )(6) 的特解.

lim _(xarrow dfrac {pi )(2)}((sin x))^tan x=（ ）（ ）