（请画图➕解答过程）3.交换积分次序:-|||-(1) (int )_(0)^1dx(int )_(x)^sqrt (x)f(x,y)dy;

二重积分(int )_(0)^1dx(int )_((x-1))^2f(x,y)dy,交换积分次序的结果是__________.二重积分交换积分次序的结果是__

在下列积分中改变累次积分的顺序:-|||-(1) (int )_(0)^2dx(int )_({x)^2x}f(x,y)dy;-|||-(2) (int )_(

设 iint_(D) f(x, y)dx dy = int_(0)^1 dx int_(0)^1-x f(x, y)dy，则改变其积分次序后为A. $\int_

24.证明: (int )_(0)^1dx(int )_(0)^xf(x-y)dy=(int )_(0)^1f(x)(1-x)dx-|||-"f(x-y)dy=

(int )_(0)^1dx(int )_(x)^1(e)^-(y^2)dy= () .-|||-

3.设I=int_(0)^1dxint_(0)^x^(2)f(x,y)dy+int_(1)^2dxint_(0)^2-xf(x,y)dy，则交换积分次序后，I可

计算(int )_(0)^1dx(int )_(1-x)^sqrt (1-{x^2)}dfrac (x+y)({x)^2+(y)^2}dy=-|||-dv=__

12.化下列二次积分为极坐标形式的二次积分:-|||-(3) (int )_(0)^1dx(int )_(1-x)^sqrt (1-{x^2)}f(x,y)dy

1.交换积分次序：int_(1)^2dxint_((1)/(x))^xf(x,y)dy.1.交换积分次序：$\int_{1}^{2}dx\int_{\frac{

12.化下列二次积分为极坐标形式的二次积分:-|||-(1) (int )_(0)^1dx(int )_(0)^1f(x,y)dy;-|||-(2) (int