在下列积分中改变累次积分的顺序:-|||-(1) (int )_(0)^2dx(int )_({x)^2x}f(x,y)dy;-|||-(2) (int )_(-1)^1dx(int )_(-sqrt {1-{x)^2}}f(x,y)dy ;-|||-(3) (int )_(0)^2adx(int )_(sqrt {2ax-{x)^2}}f(x,y)dy,-|||-(4) (int )_(0)^1dx(int )_(a)^(x^2)f(x,y)dy+(int )_(1)^3dx(int )_(0)^dfrac (1{2)}(3-x)df(x,y)dy.

12.化下列二次积分为极坐标形式的二次积分:-|||-(1) (int )_(0)^1dx(int )_(0)^1f(x,y)dy;-|||-(2) (int

[例5] 积分 (int )_(0)^2dx(int )_(0)^sqrt (2x-{x^2)}sqrt ({x)^2+(y)^2}dy= __

求不定积分int dfrac (1)(2x)sqrt (ln x)dx=（）.int dfrac (1)(2x)sqrt (ln x)dx=int dfrac

(int )_(0)^1dx(int )_(x)^1(e)^-(y^2)dy= () .-|||-

（请画图➕解答过程）3.交换积分次序:-|||-(1) (int )_(0)^1dx(int )_(x)^sqrt (x)f(x,y)dy;（请画图➕解答过程）

定积分(int )_(0)^1sqrt (2x-{x)^2}dx=( )(int )_(0)^1sqrt (2x-{x)^2}dx=( )(int )_(0

(int )_(-1)^2x|x|dx=(int )_(-1)^1x|x|x+(int )_(1)^2x|x|x|=0+(int )_(1)^2(x)^2dx

计算(int )_(0)^1dx(int )_(1-x)^sqrt (1-{x^2)}dfrac (x+y)({x)^2+(y)^2}dy=-|||-dv=__

[例5] 设函数f(x,y)连续,则 (int )_(1)^2dx(int )_(x)^2f(x,y)dy+(int )_(1)^2dy(int )_(y)^4

二重积分(int )_(0)^1dx(int )_((x-1))^2f(x,y)dy,交换积分次序的结果是__________.二重积分交换积分次序的结果是__