(int )_(-1)^2x|x|dx=(int )_(-1)^1x|x|x+(int )_(1)^2x|x|x|=0+(int )_(1)^2(x)^2dx ()-|||-A 对-|||-B 错

参考答案与解析:

相关试题

求不定积分int dfrac (1)(2x)sqrt (ln x)dx=().int dfrac (1)(2x)sqrt (ln x)dx=int dfrac (1)(2x)sqrt (ln x)dx

求不定积分int dfrac (1)(2x)sqrt (ln x)dx=().int dfrac (1)(2x)sqrt (ln x)dx=int dfrac

  • 查看答案
  • (int )_(1)^2dfrac (dx)(x(1+sqrt {2x))}=( )A.(int )_(1)^2dfrac (dx)(x(1+sqrt {2x))}=( )B.(int )_(1)

    (int )_(1)^2dfrac (dx)(x(1+sqrt {2x))}=( )A.(int )_(1)^2dfrac (dx)(x(1+sqrt {2x

  • 查看答案
  • int (2x^2)/(x^2 + 1) dx = ( )

    int (2x^2)/(x^2 + 1) dx = ( )A. $2x - 2\arctan x + C$B. $x^2 - 2\arctan x + C$C.

  • 查看答案
  • int dfrac (1)(x{ln )^2x}dx

    int dfrac (1)(x{ln )^2x}dx

  • 查看答案
  • 在下列积分中改变累次积分的顺序:-|||-(1) (int )_(0)^2dx(int )_({x)^2x}f(x,y)dy;-|||-(2) (int )_(-1)^1dx(int )_(-sqrt

    在下列积分中改变累次积分的顺序:-|||-(1) (int )_(0)^2dx(int )_({x)^2x}f(x,y)dy;-|||-(2) (int )_(

  • 查看答案
  • ( 单选题 ) int dfrac ({e)^x}(1+{e)^2x}dx=_________int dfrac ({e)^x}(1+{e)^2x}dx=int dfrac ({e)^x}(1+{e)

    ( 单选题 ) int dfrac ({e)^x}(1+{e)^2x}dx=_________int dfrac ({e)^x}(1+{e)^2x}dx=int

  • 查看答案
  • (int )_(0)^dfrac (pi {4)}dfrac (x)(1+cos 2x)dx=( ) .(int )_(0)^dfrac (pi {4)}dfrac (x)(1+cos 2x)dx=(

    (int )_(0)^dfrac (pi {4)}dfrac (x)(1+cos 2x)dx=( ) .(int )_(0)^dfrac (pi {4)}dfr

  • 查看答案
  • ()-|||-(2) (int )_(-infty )^+infty dfrac (2x)(1+{x)^2}dx=lim _(aarrow +infty )(int )_(-a)^adfrac (2x

    ()-|||-(2) (int )_(-infty )^+infty dfrac (2x)(1+{x)^2}dx=lim _(aarrow +infty )(i

  • 查看答案
  • .int dfrac (1+{cos )^2x}(1+cos 2x)dx

    .int dfrac (1+{cos )^2x}(1+cos 2x)dx

  • 查看答案
  • 定积分(int )_(0)^1sqrt (2x-{x)^2}dx=( )(int )_(0)^1sqrt (2x-{x)^2}dx=( )(int )_(0)^1sqrt (2x-{x)^2}dx

    定积分(int )_(0)^1sqrt (2x-{x)^2}dx=( )(int )_(0)^1sqrt (2x-{x)^2}dx=( )(int )_(0

  • 查看答案