(int )_(1)^2dfrac (dx)(x(1+sqrt {2x))}=( )A.(int )_(1)^2dfrac (dx)(x(1+sqrt {2x))}=( )B.(int )_(1)^2dfrac (dx)(x(1+sqrt {2x))}=( )C.(int )_(1)^2dfrac (dx)(x(1+sqrt {2x))}=( )D.(int )_(1)^2dfrac (dx)(x(1+sqrt {2x))}=( )

(40 ) int dfrac (dx)(1+sqrt {2x)};

40) int dfrac (dx)(1+sqrt {2x)} ,

求不定积分int dfrac (1)(2x)sqrt (ln x)dx=（）.int dfrac (1)(2x)sqrt (ln x)dx=int dfrac

(int )_(1)^2dfrac (sqrt {{x)^2-1}}(x)dx

不定积分int dfrac (1)(1+sqrt {x)}dx= __ 。（） int dfrac (1)(1+sqrt {x)}dx= __ 。

不定积分int dfrac (1)(1+sqrt {1-x)}dx=( ) int dfrac (1)(1+sqrt {1-x)}dx=int dfrac (

(1) int dfrac (dx)(1+sqrt {1-{x)^2}} ,

(6) int dfrac (dx)(1+sqrt {1-{x)^2}} ;

(25) int dfrac (1)(1+sqrt {1-{x)^2}}dx ;

int dfrac (dx)(1+sqrt [3]{x+1)}