int dfrac (dx)(1+sqrt [3]{x+1)}

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求int dfrac (dx)(1+sqrt [3]{x+1)}.

求int dfrac (dx)(1+sqrt [3]{x+1)}.求.

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    • 不定积分int dfrac (1)(1+sqrt {x)}dx= __ 。（） int dfrac (1)(1+sqrt {x)}dx= __ 。

    不定积分int dfrac (1)(1+sqrt {x)}dx= __ 。（） int dfrac (1)(1+sqrt {x)}dx= __ 。

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    • 不定积分int dfrac (1)(1+sqrt {1-x)}dx=( ) int dfrac (1)(1+sqrt {1-x)}dx=int dfrac (1)(1+sqrt {1-x)}dx=i

    不定积分int dfrac (1)(1+sqrt {1-x)}dx=( ) int dfrac (1)(1+sqrt {1-x)}dx=int dfrac (

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    • (int )_(1)^2dfrac (dx)(x(1+sqrt {2x))}=( )A.(int )_(1)^2dfrac (dx)(x(1+sqrt {2x))}=( )B.(int )_(1)

    (int )_(1)^2dfrac (dx)(x(1+sqrt {2x))}=( )A.(int )_(1)^2dfrac (dx)(x(1+sqrt {2x

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    • (1) int dfrac (dx)(1+sqrt {1-{x)^2}} ,

    (1) int dfrac (dx)(1+sqrt {1-{x)^2}} ,

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    • 求 (int )_(0)^8dfrac (1)(1+sqrt [3]{x)}dx

    求 (int )_(0)^8dfrac (1)(1+sqrt [3]{x)}dx

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    • 定积分(int )_(0)^4dfrac (dx)(1+sqrt {x)}的值是（ ）(int )_(0)^4dfrac (dx)(1+sqrt {x)}(int )_(0)^4dfrac (dx)

    定积分(int )_(0)^4dfrac (dx)(1+sqrt {x)}的值是（ ）(int )_(0)^4dfrac (dx)(1+sqrt {x)}(i

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    • int dfrac (dx)(sqrt [3]{{(x+1))^2((x-1))^4}}

    int dfrac (dx)(sqrt [3]{{(x+1))^2((x-1))^4}}

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    • int dfrac (dx)(sqrt [3]{{(x+1))^2((x-1))^4}}

    int dfrac (dx)(sqrt [3]{{(x+1))^2((x-1))^4}}

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    • int dfrac (dx)(sqrt [3]{{(x+1))^2((x-1))^4}}

    int dfrac (dx)(sqrt [3]{{(x+1))^2((x-1))^4}}

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