求int dfrac (dx)(1+sqrt [3]{x+1)}.求.
不定积分int dfrac (1)(1+sqrt {x)}dx= __ 。() int dfrac (1)(1+sqrt {x)}dx= __ 。
不定积分int dfrac (1)(1+sqrt {1-x)}dx=( ) int dfrac (1)(1+sqrt {1-x)}dx=int dfrac (
int dfrac (dx)(1+sqrt [3]{x+1)}
定积分(int )_(0)^4dfrac (dx)(1+sqrt {x)}的值是( )(int )_(0)^4dfrac (dx)(1+sqrt {x)}(i
(int )_(1)^2dfrac (dx)(x(1+sqrt {2x))}=( )A.(int )_(1)^2dfrac (dx)(x(1+sqrt {2x
【题目】-|||-(int )_(0)^4dfrac (1)(1+sqrt {x)}dx.
(1) int dfrac (dx)(1+sqrt {1-{x)^2}} ,
求不定积分int(1)/((1+sqrt[3](x))sqrt(x))dx.21. 求不定积分$\int\frac{1}{(1+\sqrt[3]{x})\sqr
(6) int dfrac (dx)(1+sqrt {1-{x)^2}} ;