40) int dfrac (dx)(1+sqrt {2x)} ,
(int )_(1)^2dfrac (dx)(x(1+sqrt {2x))}=( )A.(int )_(1)^2dfrac (dx)(x(1+sqrt {2x
不定积分int dfrac (1)(1+sqrt {x)}dx= __ 。() int dfrac (1)(1+sqrt {x)}dx= __ 。
求不定积分int dfrac (1)(2x)sqrt (ln x)dx=().int dfrac (1)(2x)sqrt (ln x)dx=int dfrac
不定积分int dfrac (1)(1+sqrt {1-x)}dx=( ) int dfrac (1)(1+sqrt {1-x)}dx=int dfrac (
(1) int dfrac (dx)(1+sqrt {1-{x)^2}} ,
(6) int dfrac (dx)(1+sqrt {1-{x)^2}} ;
(25) int dfrac (1)(1+sqrt {1-{x)^2}}dx ;
定积分(int )_(0)^4dfrac (dx)(1+sqrt {x)}的值是( )(int )_(0)^4dfrac (dx)(1+sqrt {x)}(i
int dfrac (dx)(1+sqrt [3]{x+1)}