(int )_(1)^2dfrac (sqrt {{x)^2-1}}(x)dx

(int )_(1)^2dfrac (dx)(x(1+sqrt {2x))}=( )A.(int )_(1)^2dfrac (dx)(x(1+sqrt {2x

计算下列定积分.-|||-(int )_(sqrt {2)}^2dfrac (dx)(xsqrt {{x)^2-1}} ;

int dfrac (1)(sqrt {{x)^2-1}}dx 时应该令 int dfrac (1)(sqrt {{x)^2-1}}dx以化去根在计算式 A 对

不定积分 int dfrac ({x)^2-1}(sqrt {xsqrt {x)}}dx=

求不定积分int dfrac (1)(2x)sqrt (ln x)dx=（）.int dfrac (1)(2x)sqrt (ln x)dx=int dfrac

1.微分方程(1-(x)^2)(y)^2dfrac (dy)(dx)+(2(x)^2-1)(y)^3=(x)^3是(1-(x)^2)(y)^2dfrac (dy

)int dfrac (dx)(2{x)^2-1};

(1) (int )_(0)^2dfrac (dx)({(1-x))^2}

(int )_(0)^2dfrac (dx)({(1-x))^2};;

(int )_(0)^2dfrac (dx)({(1-x))^2};