计算下列广义积分:(int )_(1)^+infty dfrac (dx)(xsqrt {2{x)^2-1}}计算下列广义积分:
不定积分 int dfrac ({x)^2-1}(sqrt {xsqrt {x)}}dx=
计算下列定积分.-|||-(int )_(dfrac {sqrt {2)}(2)}^1dfrac (sqrt {1-{x)^2}}({x)^2}dx -
(int )_(1)^2dfrac (sqrt {{x)^2-1}}(x)dx
1.计算下列定积分:-|||-(8) (int )_(dfrac {1)(sqrt {2)}}^1dfrac (sqrt {1-{x)^2}}({x)^2}dx
.计算下列定积分:-|||-(10) (int )_(1)^sqrt (3)dfrac (dx)({x)^2sqrt (1+{x)^2}}
1.计算下列定积分:-|||-(10) (int )_(1)^sqrt (3)dfrac (dx)({x)^2sqrt (1+{x)^2}};
1.计算下列定积分:-|||-(16)(int )_(1)^(e^2)dfrac (dx)(xsqrt {1+ln x)};
计算下列定积分:(int )_(0)^sqrt (2)sqrt (2-{x)^2}dx;计算下列定积分:;
int dfrac (dx)(xsqrt {{x)^2-1}}=____________________________