证明 :(int )_(x)^1dfrac (dt)(1+{t)^2}=(int )_(1)^dfrac (1{x)}dfrac (dt)(1+{t)^2}(xgt 0).

参考答案与解析:

相关试题

3.证明: (int )_(x)^1dfrac (dt)(1+{t)^2}=(int )_(1)^dfrac (1{x)}dfrac (dt)(1+{t)^2}(xgt 0),

3.证明: (int )_(x)^1dfrac (dt)(1+{t)^2}=(int )_(1)^dfrac (1{x)}dfrac (dt)(1+{t)^2}

  • 查看答案
  • 3.证明: (int )_(x)^1dfrac (dt)(1+{t)^2}=(int )_(1)^dfrac (1{x)}dfrac (dt)(1+{t)^2}(xgt 0).

    3.证明: (int )_(x)^1dfrac (dt)(1+{t)^2}=(int )_(1)^dfrac (1{x)}dfrac (dt)(1+{t)^2}

  • 查看答案
  • 分) 设 (x)=(int )_({x)^2}dfrac (t)(sqrt {1+{t)^3}}dt 求 =(int )_(0)^1xF(x)dx

    分) 设 (x)=(int )_({x)^2}dfrac (t)(sqrt {1+{t)^3}}dt 求 =(int )_(0)^1xF(x)dx

  • 查看答案
  • lim _(xarrow 0)dfrac (x{int )_(0)^x((e)^2t-1)dt}(ln (1+{x)^3)}。

    lim _(xarrow 0)dfrac (x{int )_(0)^x((e)^2t-1)dt}(ln (1+{x)^3)}。。

  • 查看答案
  • 求下列极限: lim _(xarrow 0)[ dfrac ({int )_(0)^xsqrt (1+{t)^2}dt}(x)+dfrac ({int )_(0)^xsin tdt}({x)^2}]

    求下列极限: lim _(xarrow 0)[ dfrac ({int )_(0)^xsqrt (1+{t)^2}dt}(x)+dfrac ({int )_(0

  • 查看答案
  • 计算下列各导数:-|||-(1) dfrac (d)(dx)(int )_(0)^(x^2)sqrt (1+{t)^2}dt;-|||-(2) dfrac (d)(dx)(int )_({x)^2}^

    计算下列各导数:-|||-(1) dfrac (d)(dx)(int )_(0)^(x^2)sqrt (1+{t)^2}dt;-|||-(2) dfrac (d

  • 查看答案
  • 5.计算下列各导数:-|||-(1) dfrac (d)(dx)(int )_(0)^(x^2)sqrt (1+{t)^2}dt;-|||-(2) dfrac (d)(dx)(int )_({x)^2

    5.计算下列各导数:-|||-(1) dfrac (d)(dx)(int )_(0)^(x^2)sqrt (1+{t)^2}dt;-|||-(2) dfrac

  • 查看答案
  • int dfrac ({x)^3}({(1+{x)^2)}^2}dx=A.int dfrac ({x)^3}({(1+{x)^2)}^2}dx=B.int dfrac ({x)^3}({(1+{x)^

    int dfrac ({x)^3}({(1+{x)^2)}^2}dx=A.int dfrac ({x)^3}({(1+{x)^2)}^2}dx=B.int df

  • 查看答案
  • (x)=(int )_(0)^(x^2)dfrac (dt)(sqrt {1+{t)^4}}的单调减少区间是________.

    (x)=(int )_(0)^(x^2)dfrac (dt)(sqrt {1+{t)^4}}的单调减少区间是________.的单调减少区间是________.

  • 查看答案
  • (int )_(-1)^1dfrac (1+sin x)(1+{x)^2}dx .

    (int )_(-1)^1dfrac (1+sin x)(1+{x)^2}dx .

  • 查看答案