(int )_(-1)^1dfrac (1+sin x)(1+{x)^2}dx .

参考答案与解析：

相关试题

(int )_(-1)^1(dfrac (sin x+1)(1+{x)^2}+(x)^4)dxA (int )_(-1)^1(dfrac (sin x+1)(1+{x)^2}+(x)^4)dx B

(int )_(-1)^1(dfrac (sin x+1)(1+{x)^2}+(x)^4)dxA (int )_(-1)^1(dfrac (sin x+1)(

  • 查看答案

    • 计算int dfrac (dx)(cos x(1+sin x))

    计算int dfrac (dx)(cos x(1+sin x))计算

  • 查看答案

    • int dfrac (sin x)(1+{cos )^2x}dx=-|||-__

    int dfrac (sin x)(1+{cos )^2x}dx=-|||-__

  • 查看答案

    • int dfrac ({x)^3}({(1+{x)^2)}^2}dx=A.int dfrac ({x)^3}({(1+{x)^2)}^2}dx=B.int dfrac ({x)^3}({(1+{x)^

    int dfrac ({x)^3}({(1+{x)^2)}^2}dx=A.int dfrac ({x)^3}({(1+{x)^2)}^2}dx=B.int df

  • 查看答案

    • 证明 :(int )_(x)^1dfrac (dt)(1+{t)^2}=(int )_(1)^dfrac (1{x)}dfrac (dt)(1+{t)^2}(xgt 0).

    证明 :(int )_(x)^1dfrac (dt)(1+{t)^2}=(int )_(1)^dfrac (1{x)}dfrac (dt)(1+{t)^2}(x

  • 查看答案

    • 计算下列定积分。-|||-(int )_(0)^1dfrac ({x)^4}(1+{x)^2}dx

    计算下列定积分。-|||-(int )_(0)^1dfrac ({x)^4}(1+{x)^2}dx

  • 查看答案

    • (int )_(0)^1dfrac (x+2)(sqrt {x+1)}dx=( )(int )_(0)^1dfrac (x+2)(sqrt {x+1)}dx=( );(int )_(0)^1dfr

    (int )_(0)^1dfrac (x+2)(sqrt {x+1)}dx=( )(int )_(0)^1dfrac (x+2)(sqrt {x+1)}dx=

  • 查看答案

    • 计算不定积分int dfrac (x)(1+sin x)dx

    计算不定积分int dfrac (x)(1+sin x)dx计算不定积分

  • 查看答案

    • (int )_(0)^1dfrac (dx)({x)^2sqrt (1-x)} 发散-|||-D (int )_(0)^1dfrac (dx)(xsqrt {1-x)} 发散

    (int )_(0)^1dfrac (dx)({x)^2sqrt (1-x)} 发散-|||-D (int )_(0)^1dfrac (dx)(xsqrt {1

  • 查看答案

    • (B)| (x/(1+2)^2 (1+x^2)^2 dx=0.-|||-(C) (int )_(-1)^1dfrac (1)(sin x)dx=0. (D) (int )_(-infty )^+inf

    (B)| (x/(1+2)^2 (1+x^2)^2 dx=0.-|||-(C) (int )_(-1)^1dfrac (1)(sin x)dx=0. (D) (

  • 查看答案