.=dfrac (1)(6)m(l)^2(omega )^2-|||-A B

=dfrac ({n)^2h}(8m/{s)^2}-|||-B omega =(x)=sqrt (dfrac {2)(t)}sin (dfrac ({n)^2p

1 6-|||-3 2-|||-2-|||-6A). 1 6-|||-3 2-|||-2-|||-6A). 1 6-|||-3 2-|||-2-|||-6A).

3 一质量M,半径为R的圆柱-|||-omega =dfrac (2{v)_(0)}(R)-|||-omega =dfrac (m{v)_(0)}((M+m)R

._(2)gt (n)_(1) L-|||-P-|||-i D 2-|||-B =2esqrt ({{n)_(2)}^2-({n)_(1)}^2}(sin )^

下列凑微分的形式中错误的是( )A dfrac (1)(sqrt {{a)^2-(x)^2}}dx=d(arctan dfrac (x)(a))B dfr

(a)_(m)+(b)_(1)+(b)_(2)+... +(b)_(n)}(m+n)=-|||-dfrac (m)(m+n)cdot dfrac ({a)_(1

l 2l 然-|||-2 2一 3 3-|||-(c) (d)-|||-P q 11 2-|||-A 11 12 A B-|||-B C-|||-1 2 C 1

(B) dfrac (x)(y)((y+1))^2-|||-(C) ^2((x+dfrac {1)(x))}^2. (D) dfrac (y)(x)((y+1)

24、单选-|||-设 -|||-A 2-|||-B dfrac (1)(2)-|||-C 1-|||-D 0

2、单选 设随机变量X服从正态分布N-|||-A =dfrac (1)(2) =1-|||-B =2, b=-2-|||-C a=-2 =-1-|||-D =d