(int )_(-sqrt {2)}^sqrt (2)sqrt (8-2{y)^2}dy ;

参考答案与解析：

相关试题

计算(int )_(-sqrt {2)}^sqrt (2)sqrt (8-2{y)^2}dy-|||-__

计算(int )_(-sqrt {2)}^sqrt (2)sqrt (8-2{y)^2}dy-|||-__计算

  • 查看答案

    • [例5] 积分 (int )_(0)^2dx(int )_(0)^sqrt (2x-{x^2)}sqrt ({x)^2+(y)^2}dy= __

    [例5] 积分 (int )_(0)^2dx(int )_(0)^sqrt (2x-{x^2)}sqrt ({x)^2+(y)^2}dy= __

  • 查看答案

    • 已知x=(sqrt(3)-sqrt(2))/(sqrt(3)+sqrt(2))，y=(sqrt(3)+sqrt(2))/(sqrt(3)-sqrt(2))，求3x2-5xy+3y2的值．

    已知x=(sqrt(3)-sqrt(2))/(sqrt(3)+sqrt(2))，y=(sqrt(3)+sqrt(2))/(sqrt(3)-sqrt(2))，求3

  • 查看答案

    • (int )_(0)^sqrt (2)sqrt (2-{x)^2}dx

    (int )_(0)^sqrt (2)sqrt (2-{x)^2}dx

  • 查看答案

    • 五.计算积分int_(-1)^1dyint_(1+sqrt(1-y^2))^sqrt(2-y^(2))(sqrt(x^2)+y^(2)+sin^3y)dx

    五.计算积分int_(-1)^1dyint_(1+sqrt(1-y^2))^sqrt(2-y^(2))(sqrt(x^2)+y^(2)+sin^3y)dx五.(

  • 查看答案

    • [题目] (int )_(0)^sqrt (2)sqrt (2-{x)^2}dx= __

    [题目] (int )_(0)^sqrt (2)sqrt (2-{x)^2}dx= __

  • 查看答案

    • [题目] (int )_(0)^sqrt (2)sqrt (2-{x)^2}dx

    [题目] (int )_(0)^sqrt (2)sqrt (2-{x)^2}dx

  • 查看答案

    • 计算: (int )_(0)^sqrt (2)sqrt (2-{x)^2}dx= ．

    计算: (int )_(0)^sqrt (2)sqrt (2-{x)^2}dx= ．计算: ．

  • 查看答案

    • (3)曲线 ) 与圆柱面 ^2+{y)^2=4 的交点为 () .-|||-(A) (sqrt (2),sqrt (2),pm 2) (B) (sqrt (2),sqrt (2),2)-|||-(

    (3)曲线 ) 与圆柱面 ^2+{y)^2=4 的交点为 () .-|||-(A) (sqrt (2),sqrt (2),pm 2) (B) (sqrt (

  • 查看答案

    • sqrt (2)pi :2 C. sqrt (2)pi :4 D. sqrt (2)pi :8

    sqrt (2)pi :2 C. sqrt (2)pi :4 D. sqrt (2)pi :8

  • 查看答案