[题目] (int )_(0)^sqrt (2)sqrt (2-{x)^2}dx
(int )_(0)^sqrt (2)sqrt (2-{x)^2}dx
计算: (int )_(0)^sqrt (2)sqrt (2-{x)^2}dx= .计算: .
(int )_(-pi )^pi sqrt ({pi )^2-(x)^2}dx= )(int )_(-pi )^pi sqrt ({pi )^2-(x)^2}d
计算下列积分:(int )_(0)^sqrt (2)sqrt (2-{x)^2}dx.计算下列积分:.
计算下列定积分:(int )_(0)^sqrt (2)sqrt (2-{x)^2}dx;计算下列定积分:;
(int )_(0)^a(x)^2sqrt ({a)^2-(x)^2}dx(agt 0)
(1) (int )_(0)^a(x)^2sqrt ({a)^2-(x)^2}dx(agt 0);
(3)(int )_(0)^a(x)^2sqrt ({a)^2-(x)^2}dx(agt 0);
(14) int dfrac ({x)^2}(sqrt {{a)^2-(x)^2}}dx;