(3)(int )_(0)^a(x)^2sqrt ({a)^2-(x)^2}dx(agt 0);

(int )_(0)^a(x)^2sqrt ({a)^2-(x)^2}dx(agt 0)

(1) (int )_(0)^a(x)^2sqrt ({a)^2-(x)^2}dx(agt 0);

4.计算下列定积分:-|||-(3) (int )_(0)^a(x)^2sqrt ({a)^2-(x)^2}dx(agt 0) :

(int )_(0)^sqrt (2)sqrt (2-{x)^2}dx

[题目] (int )_(0)^sqrt (2)sqrt (2-{x)^2}dx= __

[题目] (int )_(0)^sqrt (2)sqrt (2-{x)^2}dx

计算: (int )_(0)^sqrt (2)sqrt (2-{x)^2}dx= ．计算: ．

(8) (int )_(0)^1(x)^2sqrt (1-{x)^2}dx :

int_(0)^a (x^2sqrt(a^2-x^2)),(rm dx)(a>0)$\int_{0}^{a} {x^2\sqrt{a^2-x^2}}\,{\rm

(int )_(1)^sqrt (3)dfrac (dx)({x)^2sqrt (1+{x)^2}};