(1) (int )_(0)^a(x)^2sqrt ({a)^2-(x)^2}dx(agt 0);
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(int )_(0)^a(x)^2sqrt ({a)^2-(x)^2}dx(agt 0)
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4.计算下列定积分:-|||-(3) (int )_(0)^a(x)^2sqrt ({a)^2-(x)^2}dx(agt 0) :
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[题目] (int )_(0)^sqrt (2)sqrt (2-{x)^2}dx
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计算: (int )_(0)^sqrt (2)sqrt (2-{x)^2}dx= ．
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定积分(int )_(0)^1sqrt (2x-{x)^2}dx=( )(int )_(0)^1sqrt (2x-{x)^2}dx=( )(int )_(0)^1sqrt (2x-{x)^2}dx
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定积分(int )_(0)^1sqrt (2x-{x)^2}dx=( )(int )_(0)^1sqrt (2x-{x)^2}dx=( )(int )_(0
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