_(n)=((-1))^n+1dfrac (1)(sqrt {n)}-|||-C. _(n)=sin dfrac (npi )(2)-|||-D. _(n)=d
(a)_(m)+(b)_(1)+(b)_(2)+... +(b)_(n)}(m+n)=-|||-dfrac (m)(m+n)cdot dfrac ({a)_(1
=dfrac ({n)^2h}(8m/{s)^2}-|||-B omega =(x)=sqrt (dfrac {2)(t)}sin (dfrac ({n)^2p
,dfrac (ntimes 100)(n)} B S=-|||- dfrac {1)(n),... ,dfrac (ntimes 100)(n)} C S=-
+dfrac (1)(sqrt {{n)^2+n}})= __
+dfrac (1)(sqrt {{n)^2+n}}).求下列极限:.
=dfrac (T)(2pi )leqslant [ t] =dfrac ([ O] )(2);-|||-_(2)(A)_(1)+dfrac ({M)_(y)}
+dfrac (1)(sqrt {{n)^2+n}})=1
(sigma )_(n)=sqrt (dfrac {pi (1-pi ))(n)}-|||-C. (sigma )_(overline {x)}=dfrac (
(B) dfrac (sqrt {n)(overline (X)-mu )}(S)sim t(n-1).-|||-(C) dfrac (sqrt {n)(ove